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The value of k if x2 + kx + 6 x + 2 x + 3 is

WebDec 24, 2016 · Let #f(x) = x^3+x^2+kx-15# By the remainder theorem, the remainder when #f(x)# is divided by #(x-2)# will be #f(2)# So we have: #3 = f(2) = 8+4+2k-15 = 2k-3# Add #3# to both ends to get: #6 = 2k# Divide both sides by #2# and transpose to get: #k = 3# WebYou seem to be assuming that k2 + 2k − 1 is equal to (k −1)2, which is not true. Your equation k2 + 2k − 1 = 0 is correct, and it has roots k = −1± 2 ... More Items Examples Quadratic equation x2 − 4x − 5 = 0 Trigonometry 4sinθ cosθ = 2sinθ Linear equation y = 3x + 4 Arithmetic 699 ∗533 Matrix [ 2 5 3 4][ 2 −1 0 1 3 5] Simultaneous equation

Solve x^2-2kx+k^2+k-5=0 Microsoft Math Solver

Web$\begingroup$ We just wrote an equation, specifically, $2x^3+x^2+kx+6 = (x+3)P(x)$. Without doing more work, $P(x)$ could be anything, but that's ok. When you plug in $x = … WebThe values of k are precisely the solutions of Δ > 0 that's k 2 − 1 > 0, which gives k < − 1 ∨ k > 1. The quadratic formula uses b 2 − 4 a c. For there to be 2 distinct real roots, b 2 − 4 a c > … ipad model md510ll/a software upgrade https://cgreentree.com

Solve (K+2)x^2-Kx+6=0 Microsoft Math Solver

Web2 x 3 + x 2 + k x + 6 = ( x + 3) q ( x) + 0 This is an equality and must work for ALL values of x, including x = -3 : 2 ( − 3) 3 + ( − 3) 2 + k ( − 3) + 6 = ( − 3 + 3) q ( − 3) 2 ( − 3) 3 + ( − 3) 2 + k ( − 3) + 6 = 0 k can be solved You may refer factor theorem for more info Share Cite Follow answered Aug 17, 2014 at 7:59 AgentS 12k 3 33 66 WebSince x-2 is supposed to be a factor, then we should get a remainder of zero when we divide. The remainder we got, 10-2k, must then be zero: 10-2k = 0 Adding 2k: 10 = 2k Dividing by 2: 5 = k This is the value for k that makes x-2 a factor of f (x). WebSolve the equation kx x 2 + 6 = 0 for the value of x if roots of this equation are real and equal. Login Study Materials NCERT Solutions NCERT Solutions For Class 12 NCERT … ipad mobile printer bluetooth

If x^2 + kx + 6 = (x + 2)(x + 3) for all x , the value of k is

Category:Find the value of k if x2 + kx + 6 = (x+2) (x + 3) for all k

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The value of k if x2 + kx + 6 x + 2 x + 3 is

Solving for all values of k if a quadratic equation containing it has ...

WebNov 14, 2024 · Given equation is x2 – kx + 2 = 0 According to the equation, a = 1, b = – k, c = 2 For real and distnict roots, D = b 2 – 4ac &gt; 0 ⇒ (– k) 2 – 4 × 1 × 2 &gt; 0 ⇒ k 2 – 8 &gt; 0 ⇒ k2 – (2√2)2 &gt; 0 We know that, a 2 - b 2 = (a + b) (a - b) ⇒ (k - 2√2) (k + 2√2) &gt; 0 This can be possible in two ways, Case:1 (k - 2√2) &gt; 0 and (k + 2√2) &gt; 0 WebThe roots of x 2+kx+k=0 are real and equal, find k. Easy Solution Verified by Toppr Given x 2+kx+k roots are real &amp; equal ∴b 2−4ac=0 =(k) 2−4(1)(k)=0 =k 2−4k=0 =k(k−4)=0 ∴ k = 0 or k = 4 Solve any question of Quadratic Equations with:- Patterns of problems &gt; Was this answer helpful? 0 0 Similar questions

The value of k if x2 + kx + 6 x + 2 x + 3 is

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WebFind the range of values for k such that ${kx^2 + 3x + 9k = 0}$ has real roots 2 Finding roots of a quadratic equation having same roots for all real values of a parameter Weba. +1, +2, +3,16 c. †1,8 b. +1, +2, +4,8 d. +1,16 6. Find the value of m when (2x3 - mx2 + 5) is divided by (x-2) and yield a remainder of 4? b. - d. 17 7. What is the value of p so that (x-4) is a factor of x3 - (3p-2) x2 +(3p+1) x + 2(p+1)? b.-2 d. -4 8. What is the remainder of the polynomial function for the divisor to be a factor? A. O B ...

WebSep 12, 2016 · You would say f(x)=2x, so 2x=4 and you would solve the equation finding x=2. Check it: f(2)=2*2=4. Looking for an x value that gives the output value f(x) is called inverting. It is convenient to introduce a letter to hold the output. For instance, f(x)=y. We say the inverse function is the one that takes y-values and gives back x-values. WebQuestion 180851: find the value of k so that 9x^3-2x^2+kx+6/(x+2) has a remainder of 8. Answer by ptaylor(2198) (Show Source): ... (-20x^2+kx+6)-(-20x^2-40x)=x(40+k)+6 Divide (x+2) into x(40+k)+6 Third iteration, we get x(40+k)+80+2k (x(40+k))+6)-(x(40+k))+80+2k)=-74-2k --AND THIS IS THE REMAINDER Now we are told that:

WebView 3567.docx from MTH 174 at Northern Virginia Community College. 2. If y= kx where k is a constant, and y = 24 when x = 6, what is the value of y when x = 5? A) 6 B) 15 C) 20 D) … WebTo find the value of k Sol: x 2+kx+6=(x+2)(x+3) x 2+kx+6=x(x+3)+2(x+3) x 2+kx+6=x 2+3x+2x+6 x 2+kx+6=x 2+5x+6 Equating both sides in the above condition we get, The value of k=5 Was this answer helpful? 0 0 Similar questions Find k if x=3 is a root of equation kx …

WebGiven that x^2 + kx - 6 = (x-2) (x+3) We need to find k. First we will need to open the brackets on the left side and then compare the terms. ==&gt; x^2 + kx -6 = x^2 -2x + 3x - 6. ==&gt; x^2 + …

Web2x2+-3x-20=0 Two solutions were found : x = -5/2 = -2.500 x = 4 Step by step solution : Step 1 :Equation at the end of step 1 : (2x2 - 3x) - 20 = 0 Step 2 :Trying to factor by splitting ... open opticalWebJun 1, 2024 · Find the value of k if x2 + kx + 6 = (x +2) (x + 3) for all k. * See answer Advertisement Advertisement sivakumar313 sivakumar313 Step-by-step explanation: x2+kx+6=(x+2)(x+3) x2+kx+6=x(x+3)+2(x+3) x2+kx+6=x2+3x+2x+6. x2+kx+6=x2+5x+6. here x2 and 6 get cancelled and we get. kx=5x. where k becomes . k=5x÷x. open opticsWebStart your trial now! First week only $4.99! arrow_forward Literature guides Concept explainers Writing guide Popular textbooks Popular high school textbooks Popular Q&A Business Accounting Business Law Economics Finance Leadership Management Marketing Operations Management Engineering AI and Machine Learning Bioengineering Chemical … open optical network