WebEngineering Computer Science 2. Choose the assembler codes to move the value 5678h from physical memory location: 1234h to accumulator (DS=100h). a) mov ax, 1234h b) mov ax, 5678hc) mov ax, (1234h) d) mov ax, [5678h]e) mov ax, [234h] D mov ax, [4678h] 2. Choose the assembler codes to move the value 5678h from physical memory location: … WebMOV AX,BҮТE1 AX=1234H AX= d. ADD DL,BYTE DX=0122H DX= e. INC DX DX=FF12H DX= f. INC DL DX=FF23H DX= g. XCHG AL,AH AX=1234H AX= h. SUB CL,CH CX=3451H CX= Question For each of the following unrelated instructions, show the result in the destination operand. Indicate if the instruction is invalid. Assume BYTE1 is defined as DB 05.
I8086 Instruction Set-With Examples PDF - Scribd
Webmov ax,00FFh inc ax ; AX = 0100h mov ax,00FFh inc al ; AX = 0000h Show the value of the destination operand after each of the following instructions executes: .data myByte BYTE … the property group hamilton
assembly - What "MOV AX, [BX]" actually does? - Stack Overflow
Webanswer bank (DX=FFFFh, AX=80C0h / shl ebx, 3 / shl ebx, 5) 18. What will be the hexadecimal values of DX and AX after the following instructions have executed? mov ax, 3456h mov dx, 12h mov bx, 10h div bx Choose one answer. a. DX=0006h, AX=2345h b. DX=1234h, AX=0056h c. DX=0056h, AX=1234h d. cannot be determined 19. WebNo, AX cannot store the value +32,768 because it is larger than a signed word. To determine if a value is valid or not, after the negation you would need to check the status flag to see … WebORG 100h LEA AX, m RET m DW 1234h END AX is set to: 0104h. LEA instruction takes 3 bytes, RET takes 1 byte, we start at 100h, so the address of 'm' is 104h. LES REG, memory Load memory double word into word register and ES. Algorithm: REG = first word; ES = second word; Example: ORG 100h LES AX, m RET m DW 1234h DW 5678h END AX is set … the property group napier