In figure abcd is a trapezium of area 24.5
WebDec 22, 2024 · We know the area of trapezium= 1/2×( sum of parallel sides)× height so, 24.5= 1/2×(10+4)×h h= 49/14 cm= 3.5cm now, the area of circular part (ie. AEB)= 1/4 × … WebGiven Area of trapezium ABCD = 24.5 cm2→ eqn1. AD ∥ BC, AD = 10 cm, BC = 4 cm, ∠DAB = 90°. Putting the values in equation 2, we get, ⇒ AB = 3.5 cm. Therefore radius of the …
In figure abcd is a trapezium of area 24.5
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WebQuestion: In the given figure, ABCD is a trapezium of area 24.5 cm 2 , If AD BC, ∠DAB = 90°, AD = 10 cm, BC = 4 cm and ABE is quadrant of a circle, then find ... WebVDOMDHTMLtml> Q21 In the given figure, ABCD is a trapezium of area 24.5 cm2. If AD BC, ∠DAB=90, AD = 10 cm, BC - YouTube Subscribe: …
WebFeb 3, 2024 · ABCD is trapezium of area 24.5 sq.cm.in it AD BC angle DAB=90 degree AD=10cm and BC =4cm. If ABE is a quadrant of a circlefind the area of the shaded region. … WebArea of trapezium = 24.5 cm 2 Area of trapezium = a + b 2 h e i g h t [ = A D + B C 2 A B 24.5 = 10 + 4 2 A B 24.5 7 = A B AB = 3.5 cm Thus, radius = 3.5 cm Area of quadrant = Area of …
WebArea of a Segment of a Circle. Standard X Mathematics. Suggest Corrections WebIn the following figure, ABCD is a trapezium of area 24.5 cm 2 , If AD BC, ∠DAB = 90°, AD = 10 cm, BC = 4 cm and ABE is quadrant of a circle, then find the area of the shaded region. [CBSE 2014] Advertisement Remove all ads Solution Area of trapezium = ( 3 π + 2) m 2 ⇒ 24. 5 = 1 2 ( 10 + 4) × A B ⇒ A B = 3. 5 c m
WebApr 12, 2024 · Here, two parallel sides of trapezium are AD and BC. and distance between them is 14 m. ∴ Area of trapezium = 1/2 (1·5 + 8) × 14. = 1/2 × 9·5 × 14 = 66 × 5 m 2. Question 3. The area of a trapezium is 360 m2, the distance between two parallel sides is 20 m and one of the parallel side is 25 m. Find the other parallel side.
WebThe figure according to the question is shown below. Now first observe the figure carefully and then look at the solution. A s w e k n o w t h a t a r e a o f t r a p e z i u m = 1 2 × ( s u m o f p a r a l l e l s i d e s ) × d i s tan c e b e t w e e n t h e p a r a l l e l s i d e s H e n c e a c c o r d i n g t o t h e f i g u r e a r e a ... tele2 butikerWebApr 15, 2024 · Now area of trapezium = 1 2 × (sum of parallel sides) × height = 1 2 × (40 + 55) × 20 = 95 × 10 = 950 cm 2 Hence, area of given trapezium is 950 cm2. 6.4 Some important formulas related to plane figures. tele 1 ugur dundarWebJan 12, 2024 · Solution For 4. In figure, ABCD is a trapezium of area 24.5 sq. cm. in it, AD∥BC,∠DAV=90∘,AD =10 cm and BC=4 cm. if ABE is a quadrant of a circle, find the area ... tele2 5g parklajuma karteWebMar 15, 2024 · In figure, ABCD is a trapezium of area 24.5 sq. cm. In it, AD BC, ∠DAB = 90°, AD = 10 cm and BC = 4 cm. If ABE is a quadrant of a circle, find the area of the shaded region. [Take π=22/7] cbse class-10 1 Answer 0 votes answered Mar 15, 2024 by santoshjha (143k points) selected Mar 27, 2024 by Vikash Kumar Best answer tele 2 abonnemang utan surfWebIn the given figure, ABCD is a trapezium of area 24.5 cm 2 , If AD BC, ∠DAB = 90°, AD = 10 cm, BC = 4 cm and ABE is quadrant of a circle, then find the area of the shaded region. … tele 27 pulgadas barataWebIn figure, ABCD is a trapezium of area 24.5 sq. cm. In it, AD BC, ∠ DAB = 90°, AD = 10 cm and BC = 4 cm. If ABE is a quadrant of a circle, find the area of the shaded region 2. In figure, ABDC is a quadrant of a circle of radius 28 cm and a semicircle BEC is drawn with BC as diameter. Find B the area of the shaded region. 3. tele 2000 huantaWebAnswer this please Q In figure ABCD is a trapezium of area 24 5 sq cm In it, AD ∥ BC, ∠DAB=90 , AD = 10 cm and BC = 4 cm If ABE is a quadrant of a circle, find ... tele2 butik götgatan