Web10 mrt. 2024 · If the remainder when x is divided by 4 is 3, then the remainder when (2024 + x)2024 is divided by 8 is .......... jee jee main jee main 2024 Please log in or register to … WebUse the remainder theorem to find the remainder when the polynomial p (x) is divided by the given binomial.1. p (x) = x4 + x3 – 13x2 – 25x - 12; x - 42. p (x) = x3 + 4x2 + 3x – 2; x - 33. p (x) = 3x3 + 14x2 + 13x - 6; x + 2 Answer: 1.p (4)= -4 2.p (3)=70 3.p (-2)=0 Step-by-step explanation: 1.p (x)= x⁴ + x³ -13x²-25x-12;x=4
If $x$ is the remainder when a multiple of $4$ is divided by …
WebRemainder Theorem is used that when a polynomial f (x) is divided by a linear factor in the form of x-a. Go through the following steps and use them while solving the remainder of a polynomial expression in fraction of seconds. Let us take polynomial f (x) as dividend and linear expression as divisor. Web17 jan. 2024 · If there is a remainder from this division, add another zero to the dividend and add the remainder to that. Continue in this fashion until there is either: no … Still, there's more to math than just that and more to Omni's subtraction calculator … log 9 6561 = 4. log 2 128 = 7. For completeness, let's finish with a quick … Let us first recall what "divisibility" means. We say that a natural number n is … 3.5 and 4.5 are rounded to 4. It prevents cumulative rounding errors and this is … The primary method used to estimate the greatest common divisor is to find all of … tara barrack pa
If the expression ax^4 + bx^3 - x^2 + 2x + 3 has remainder 4x - Toppr Ask
Web7 jan. 2024 · 1) When x is divided by 6, the remainder is 2 2) When x is divided by 15, the remainder is 2 From F.S 1, we have that x = 6k+2, where k is a non-negative integer constant. Required to find x = 3p+r, where p= again a non-negative integer constant. We can see that for some value, 6k = 3 ∗ ( 2 k) = 3p. WebAlgebra Polynomial Division Calculator Step 1: Enter the expression you want to divide into the editor. The polynomial division calculator allows you to take a simple or complex … WebAnswer (1 of 12): It is possible to write the function x^{1999} as, x^{1999} = M.(x^2 - 1) + (Ax + B), where M is a function in x and A and B are constants. After this the problem gets easier. Now, in the above equation, put x = 1. Then, 1 = A + B ----- (2) Also , putting x = … tarabarov island